Comments

  1. C3EZ
    4 months ago
    2024-9-17 3:16:52

    The first loop put elements in linked list into a stack. the second loop will check if the stack matches linked list in transversed order (because the pop will provides the last element been pushed). If the linked list is not a palindrome then return False, otherwise return True.

  2. C3EZ
    4 months ago
    2024-9-17 3:19:30

    The best case complexity is O(n) where n is the length of linked list, and return false at first time run the second loop.
    The worst case complexity is O(2n), or O(n)where n is the length of linked list, and finsihed the second loop.

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