What will be the returned value from the following function:

def mystery(lst):    bingo = 0    for item in lst:        if bool(item):            bingo += 1    return bingo

when the value of list is [0, 1, 2, 3, None, 5, -0, 6, 7, None]

Consider the following implementation of a class for a Monash student:

class Student:    def __init__(self, name, stud_id):        self.name = name        self.stud_id = stud_id        def __gt__(self, other):        # TODO: Finish implementation

What is the purpose of this function?

def scramble(my_container):    mid = len(my_container)//2    a = my_container[mid]    b = my_container[0]    c = []    for item in my_container:        if item > a:            c.append(item)        elif item < b:            b = item     return c, b

How many times will the marked line in the following code run when the input integer is n?

def mystery(n):     stamp = 0     if n <= 0:         return 0     else:         for i in range(n):             for j in range(n):                stamp += j # This line return stamp

Answer in terms of n